June 26, 2019
Chapters
Given the absolute cumulative frequency table:
| Edad | Fi |
| [0, 2) | 4 |
| [2, 4) | 11 |
| [4, 6) | 24 |
| [6, 8) | 34 |
| [8, 10) | 40 |
1.
Calculate the arithmetic mean and standard deviation.
2.
Calculate the difference between the values that are the 10 central ages?
3.
Create the respective absolute cumulative frequency polygon.
| xi | fi | Fi | xi · fi | xi² · fi | |
| [0, 2) | 1 | 4 | 4 | 4 | 4 |
| [2, 4) | 3 | 7 | 11 | 21 | 63 |
| [4, 6) | 5 | 13 | 24 | 65 | 325 |
| [6, 8) | 7 | 10 | 34 | 70 | 490 |
| [8, 10) | 9 | 6 | 40 | 54 | 486 |
| 40 | 214 | 1368 |
Mean and Standard Deviation
2
The 10 students represent 25% of the central distribution.
Find: P37.5 y P62.5.
The 10 central ages are in the interval: [4.61, 6.2] .
Frequency Polygon
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