lim x->0 [sin-1(x-2).(tan (x-2) )/[(x-2)2 ]

I got the answer 1.Is it correct? I would be glad if I could have a detailed solution.

Scot

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amelia1977
16 March 2017
A correction should've been added,that when A approaches 0, sin A/A approaches 1 To my knowledge they are two of basic theorems in limits lim A->0 [sin A/A] = 1 and lim A->0 [tan A/A] = 1
shenaya
17 March 2017
http://www.analyzemath.com/calculus/limits/squeezing.html
shenaya
17 March 2017
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