# Finding a limit

lim x->0 [sin-1(x-2).(tan (x-2) )/[(x-2)2 ]

I got the answer 1.Is it correct? I would be glad if I could have a detailed solution.

Answers

_20170315_170002.JPG

16 March 2017

A correction should've been added,that when A approaches 0, sin A/A approaches 1
To my knowledge they are two of basic theorems in limits
lim A->0 [sin A/A] = 1
and
lim A->0 [tan A/A] = 1

17 March 2017

http://www.analyzemath.com/calculus/limits/squeezing.html

17 March 2017

Add an answer