Hi, start with putting y=0 this is where the graph intersects the x axis then put x=0 which gives a value for y this is where the graph intersects the x axis as on the x axis y=0 and on the y axis x=0
Rabia U.
15 February 2013
therefore putting y=0 x=+2,-2 so there are two values
Rabia U.
15 February 2013
after doing this you could get values inside the range when you know which are the intercepts
Rabia U.
15 February 2013
when you will draw the graph you will get a circle
Rabia U.
15 February 2013
the radius of this circle is 2
Rabia U.
15 February 2013
this is an equation of a circle
Rabia U.
15 February 2013
Thank you sooooo much!
chemfreak
19 February 2013
As people have said, it is a circle. Because it is just x^2 and y^2 and not say (x - 2)^2 it has centre (0,0) the origin. The number 4 on the right hand side is the square of the radius, so it is a circle centre (0,0) and radius 2 which means it goes through the points (0, 2) and (2, 0) and (0, - 2) and (- 2, 0)
becoach
20 February 2013
Yep, thankyou :)
chemfreak
20 February 2013 