# Integrals

Find the integral of sinx.sin2x.sin3x w.r.t. x

https://www.youtube.com/watch?v=gCUAerjff9cCheck this out, it may be a fresh perspective studying alone
mattcover
29 December 2017
You may also abbreviate the answer, iterating to ultimately...1/4[cos6x/6-cos4x/4+cos2x/2)] + constant
mattcover
29 December 2017
To mention, the obvious increasing order of co-efficient to sin, mapps somewhere to the decreasing coeff orders arranged in cos, where somewhere all the time in operation is the available substitution, sinx = 1-cosx.
mattcover
29 December 2017
http://www.epcc.edu/OfficeofStudentSuccess/tutorialservices/tutorialsupportservicesMDP/Documents/Tri...Everything for complicated calculus up to parameters etc and before iterative methods, and the foundation for the aforementioned also.
mattcover
29 December 2017
IMG_20171229_205824.jpg
erkamath
29 December 2017
Hi aiesha Please reply if satisfied with my solution.
erkamath
29 December 2017
Hello erkamath. May I ask you if you have a way to reach the answer if you had to operate 3 substitutions? I mean, could you break it down to eg ;u.v.w.  where each are a factor of the total amount/polynomial.perhaps if as you suggest in rearrangement the answer will reach by performing w.u.v to rearrange as desired....Your opinion would be appreciated,M. CoverUni of Greenwich CMS 08 - Present, Student Ambassador, Pre chartered researchman in award as present. MMath City Uni 05
mattcover
29 December 2017
When you apply u.v.w , it become complexThere is a short cut method also but for which in depth knowledge is required
erkamath
30 December 2017
erkamathYour solution really helped methankyou
aiesha
30 December 2017
Most welcome aiesha
erkamath
30 December 2017
-cos(nx)/n
Tristram D.
04 January 2018
sorry, thought that was a comma
Tristram D.
04 January 2018