The height h of a rocket above the ground, t seconds after being launched vertically with an initial

The height h of a rocket above the ground, t seconds after being launched vertically with an initial velocity of 500 feet/second, from a height of 300 feet is given by the function h=16t2+500t+300. At what time is the rocket 2800 feet above ground?

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Okay, so we want to find the time () for when the height () is 2800 feet. We have the equation: But in order to find we need to rearrange the equation to solve in terms of . What type of equation do you think the one above is?
theo.cushion
08 August 2012
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