trial and improvement

the length of the rectangle is 2cm more than its width. it has an area or 237cm sqared i need to find the width and length can you please explain what i have to do thenak you x

so let's start off with 15cm being the width which would make the length 17cm (2cm longer than the width)
chloe
05 July 2011
ok so if it's trial and improvement then you've got to start out with some estimates for what the width and length might be and then alter the numbers until you get the right result
chloe
05 July 2011
17 x 15 = 255 - now this is a little too big for the answer that we want so let's try 1cm less for the width and the length
chloe
05 July 2011
this would give us 16 x 14 = 224 - this is too small so we know that the numbers have got to be somewhere inbetween the 16x14 and the 17x 15
chloe
05 July 2011
so the most obvious starting point would be to try 16.5 x 14.5 = 239.25 - again a little too big
chloe
05 July 2011
so let's take it down a decimal place and try 16.4 x 14.4 = 236.16 - this is a little too small
chloe
05 July 2011
let's try 16.45 x 14.45= 237.7025 - now this might be close enough but if we round it up to a whole number we'd get 238 due to the .7
chloe
05 July 2011
so let's try a slightly smaller number for each with 16.44 x 14.44 = 237.3936 - this number rounds down to exactly 237 so I reckon you could use the values of 16.44 and 14.44 in your final answer
chloe
05 July 2011