Answers

please answer

09 November 2012

help

09 November 2012

The aim whenever you are asked to find the gradient and intercept of a straight line, is to rearrange your equation as y in terms of x. So take everything with y to one side, everything without y to the other, and then make sure it is of the form "y = something" and not "3y = something" or "2y = something", say. If it was 2y = something, then it follows that y = that something divided by 2. Once you have done all that, compare the following form: y = mx +c. Here m is your gradient and c is the intercept. So if you have y = 2x + 1 then the gradient we read off as 2, and the intercept we read off as 1. And so on. For your first problem, then, we divide both sides by 2 to give y = (8-x)/2 = (8/2) - (x/2) = -(1/2)*x + 4. So the gradient is -1/2, and the y-intercept is 4. Do the same sort of thing for part b yourself.

09 November 2012

Add an answer Cancel reply