# Complex calculus question

There are two graphs in the first quadant of a graph. One in the form y=(x+a)2 and one in the form y=mx+c. The two graphs intersect at two points/have two common solutions. The area of the intersect (the bit between where the lines intersect) is eqaul to one. What could the equation of the lines be?

Answers

The first step is to find the values of x1 and x2, the x coordinates of the points where the equations intersect. You'll then have to integrate the two functions between the limits x1 to x2. You know that the difference between these two integrals = 1. You apparently have 3 unknowns: m,c and a. Without solving the problem myself I can't say what deductions you can make about these constants. What progress have you made so far?

19 February 2012

pritty much at where you've described. i realise the intergral of one minus the other must equal one, but there seems to be too many variable for me to work it out algebraically

20 February 2012

It says "What could the equation of the lines be?" - to me this implies there is more than one answer, but you don't have to give a general answer.

26 February 2012

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