Function f(x)

What's the quickest way to calculate to x1 and x2 from

f(x) = ax2 + bx + c

Answers
Capture.JPG (9.99 KB)
agsapt
20 March 2013
The quadratic equation ax2 + bx + c has two roots x1 = -b + √(b2 – 4ac) 2a x2 = -b - √(b2 – 4ac) 2a
akq
20 March 2013
Roots_of_Quadratic_Equations.doc (17.5 KB)
akq
20 March 2013
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