A roller coaster car with a mass of 250kg starts from a height of 100m above the ground just before rolling down the frictionless track. Find the speed of the car as it reaches the ground
Wow, thank you so much explaining this to me!
See Jonas' solution for the correct way to solve the problem, where we consider the energy transfer from gravitational potential energy to kinetic energy. Just to show the algebra:gravitational potential energy = mgh, kinetic energy = ½mv²mgh = ½mv²m cancels from both sides: gh = ½v²rearrange to find the speed v: 2gh = v² ⇒ v = √(2gh)
use the acceleration of gravity (g)and suvathope that helped.