# Area of the shaded

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The drawing does not show what I want.

11 November 2013

My drawing did not post correctly either. Where in the drawing is the right angle of the triangle?

11 November 2013

Hi Timothy,All you have to do is draw a diagram as you have said, so: 30cm diameter circle -> draw around it the 30cm x 30cm square -> draw two lines across the square making the three 10cm divisions -> along the bottom division draw a diagonal line (thus making the 30cm base from the square and the 10cm height from the division) which will give you a right-angled triangle.Then look at the shape for the area you want, if you describe this area a bi better I can help you further, until now, draw the diagram! :)

11 November 2013

Try to draw using whiteboard but the result come out different. I will think of another way.

12 November 2013

Find the area mark "X"

12 November 2013

math-problem.pdf

12 November 2013

Hi TimothyI'm guessing this is an A-level question... There doesn't appear to be an easy trick to get the answer, so it will take a few steps. First find the intersection points of the diagonal line and the circle (call them A and B, you can do this by writing equations for the line and the lower half of the circle and solving). Then you can find the angle between those two intersection points and the center of the circle (O), and the rest should be straight forward (area of right angle triangle minus (area of sector minus area of triangle AOB)). Hope this helps, give me a shout if you need to go through the required techniques in more detail.Andy

23 November 2013

I totally agree with Rulank, draw the diagram out properly, then the solution often presents itself :)

29 November 2013

Let first write equation of circle and equation of diagonal in Cartesian coordinate syste. Find the intersection points of the diagonal and the circle.Let us call them A and B. Calculate length of chord AB by using distance formula. Apply cosine rule to calculate central angle AOB,where O is center of the circle.Required area is equal to area of the right angle triangle minus area of the minor segment AB.

16 December 2013

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