Pythagoras Theorem

a right-angled triangle with long side of (x) and short sides of (x-3) & (6). can someone please explain how to find the value of (x) ??

All questions on Maths

Answers
If the sides of the triangle are a, b and c (where c is the long side), Pythagoras found that the square of a, added to the square of b equals the square of c, so in your case x squared equals (x-3) squared + 6 squared
shaunattutorhub
28 June 2011
x^2 = (x-3)^2 + 6^2 = (x-3) (x-3) + 36 = x^2 -6x +9 + 36
shaunattutorhub
28 June 2011
therefore: X^2 = X^2-6X +45 and 6X = 45
shaunattutorhub
28 June 2011
it's late, so please check my workings!
shaunattutorhub
28 June 2011
Add an answer Cancel reply