Algebra

what is 2x ^2 -7 + 23 = 0 Its a quadratic equations

Answers
Check the question again please, you might have a wrong sign somewhere. If you solve the above equation you get 2x^2=-23+7, hence 2x^2=-16, so x^2=-8, which is an equation that doesn't have a solution within the set of the real numbers. However, if you have learned complex analysis it can be solved and I can send you the answer. The solution is an imaginary number.
marias
14 January 2018
2x^2 = 7-232x^2 = -16x^2 = -4x = 2i
paras
16 January 2018
The answer is listed in Complex form, however between lines 2 and 3 of the last answer 2x^2 onto x^2 in relation to similar operation -16, should map onto -8 as Maria S mentions primarily.It is an easy mistake to make when trying to break into negative quantity to arrange into the same function as the approximate amount for i. Particularly, the power operation present and the x co-efficiant has swung in both being  the number 2. Working clearly from line 1 introducing a negative function RHS to reach an suitable arrangement into i is also clear and commendable, certainly the only suitable way to answer totally correctly. @x^2=-8, with complex procedure you may deduce approximately the roots 2.2^1/2i & -2.2^1/2i for x
mattcover
18 January 2018
I may finally mention, as I should consider that the question is perhaps a typo in form of ax2 - bx + c = 0, where complex analysis has replaced correctly the prev. mention (exactly a=2 b=-7 and c=23)https://www.symbolab.com/solver/step-by-step/2x%5E%7B2%7D-7x%2B23%3D0 The link further directs into complex mathematics and explains thoroughly should the equation have read 2x^2-7x+23=0 (which is more difficult as exists another substituted variable x)
mattcover
18 January 2018
2x^2=-16   => x^2=-8   this equation has no real solutions!Pure imaginary roots  x=+/-2sqrt2i
Chris S.
22 January 2018
IMG_20180124_140247_1_.jpg
ramendu
24 January 2018
Very clearly there is at least a complex solution should as suggested earlier the equation have a term in x not in fact -7 + 23
mattcover
28 January 2018
Ramendu may i say working very clear and accurate, with enough appropriate statement for extensive answer. Example stuff. M Cover
mattcover
28 January 2018
2x^2 -7+23=0 , yes this is Quadratic Equation because the highest power of (Variable) x is 2.
vik
30 January 2018
It certainly is a quadratic equation, as Vik mentions the degree of the polynomial is 2. IE the highest order of x is a=2 / 2x^2.We have been mentioning whether in fact the equation is a=2 b = -7 and c = -16or a = 2 b = 0 and c = '7-23', in other words, ax^2+bx+c=0.
mattcover
30 January 2018
2x^2-7+23=0. ok so the trick to this one is visualizing the simplified form:combine like terms 2x^2+16=0
alexdelawareee
02 February 2018
Yes it's a Quadratic equation.we know thatimage: http://www.yourdictionary.com/image/articles/18925.ThinkstockPhotos-502612028.jpgA quadratic equation is an equation of the second degree, meaning it contains at least one term that is squared. The standard form is ax² + bx + c = 0 with a, b, and c being constantsHere the power of x is 2 
priancy
06 February 2018
2x^2-7+23=0 is a quadratic equation. Reason:if compared to the standard form ax^2+bx+c=0 ; a is not equal to zero,we can find it holds true to be a quadratic eqn with a=2; b=0; c=16
vinit_sinha
06 February 2018
Hi Abdul! This is how I would answer this question:We can simplify this equation into 2x^2     +16      =0 A quadratic equation looks like this: ax^2   +    bx     + c    =0The number that goes before the    x^2    is 2, so a=2There isnt any x's that are not squared, which would be for example 4x, so that means b has to be 0C is a number that is on its own with no x's, so c must be 16!Hope this helps 
Jasmine L.
11 February 2018
I think your are forgetting to multiply x with 7
rajatkumar
17 February 2018
x=+2.828i,-2.828i
sushil187
18 February 2018
I think it will be 2x^2-7x+23=0, since the highest degree of a variable (here x) is 2 its a quadratic equation, solving this means we must find out those values of x which will satisfies the equation. We can solve this by using quadratic formula.
vir
22 February 2018
If it is the same equation you have written , then2x^2-7+23 = 0=2x^2 +16=0= 2x^2 = -16=x^2 = -8=x=+2.828i,-2.828i
wintersoldier
04 March 2018
x=sqaure root of 8
nageswar.tutor
14 March 2018
2x^2=7-232x^2= -16x^2= -16/2x^2= -8X= -√8X= -2√2Where value of √2= 1.414X=  +2.828 and -2.828
sowjanya
24 April 2018
This isn't a quadratic equation, it would need one more x term (2x^2 - 7x + 23). But here is your answer: 2x^2-7 + 23 = 0 2x^2 +16 = 0 2x^2=-16 x = sqrt8
michellekempis
25 April 2018
This isn't a quadratic equation, it would need one more x term (2x^2 - 7x + 23). your answer will be : 2x^2-7 + 23 = 0 2x^2 +16 = 0 2x^2=-16 x = 2√2i and -2√2i
sitesh
03 May 2018
WP_20180517_07_54_54_Pro.jpg
pawankumar
17 May 2018
IMG_20180711_224238.jpg
panthamnani
11 July 2018
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