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Solve for x

(X-2) over 3 + 1 = x over 7

Emma

Answers
(x-2)/3 + 1 = x/7Time by 7 both sides7[(x-2)/3 + 1] = 7•x/77(x-2)/3 + 7•1 = x(7x-14)/3 -7 = xTime by 3 both sides3[(7x-14)/3 - 7] = 3x3(7x-14)/3 - 3•7 = 3x7x-14 - 21=3x7x-35=3xSubtract 3x in both sides7x-3x-35=04x-35=0Add 35 in both sides4x=35Divide by 4 both sidesX=35/4 or X=8.75
Raquel C.
19 August 2017
-7over 4
Sandipan B.
11 September 2017
(X-2) OVER 3+1 =X OVER 7 can be mathematically written as((x-2)/3)+1=(x/7)(x/3)-(x/7)=(2/3)-14x/21=-1/3x=-7/4
rishi1404
05 June 2018
(x-2)/3+1=x/7. Then multiply both sides of the equation by the LCM (lowest common multiple) of the denominators of the fraction (3 and 7) so 21. We now have, 7x-14+21=3x7x+7=3x4x=-7x=-7/4
Shiv M.
05 July 2018
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