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10 December 2012
2x+4y=1.............................eqn (1)
3x-5y=7..............................eqn (2)
10 December 2012
multiplied by 3 both side in eqn(1) and multiplied by 2 both in with eqn (2)
10 December 2012
then it will be 6x+12y=3.........................(3) and 6x-10y=14.............................(4)
10 December 2012
now we have to subtract eqn 3 to eqn 4
10 December 2012
(6x+12y)-(6x-10y)=3-14
or,6x+12y-6x+10y=-11
or,22y=-11
10 December 2012
or, y=-1/2
10 December 2012
or,y=-11/22
10 December 2012
or,2x-4/8=1
10 December 2012
2x+4(-1/2)=1
10 December 2012
now putting the value of y in eqn (1)
10 December 2012
or2x=1+4/8
10 December 2012
so the vale of x=.75 and y=1/2
or, y=.5
10 December 2012
or, 2x=1+1/2
or,2x= 1+0.5
or,2x=1.5
or,x= 1.5/2
or ,x = .75
10 December 2012
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