March 10, 2021

Chapters

## Exercise 1

Solve:

## Exercise 2

Solve:

## Exercise 3

Solve:

## Exercise 4

Calculate the values of k for which the roots of the equation x² − 6x + k = 0 are two real and distinct numbers.

## Exercise 5

Solve:

1

2

3

## Exercise 6

Solve:

## Exercise 7

Solve:

1

2

3

## Solution of exercise 1

Solve:

## Solution of exercise 2

Solve:

4x² − 4x + 1 ≤ 0

4x² − 4x + 1 = 0

## Solution of exercise 3

Solve:

The numerator is always positive.

The denominator cannot be zero.

Therefore, the original inequality will be equivalent to:

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## Solution of exercise 4

Calculate the values of k for which the roots of the equation are two real and distinct numbers.

## Solution of exercise 5

Solve:

1

2

3

## Solution of exercise 6

Solve:

## Solution of exercise 7

Solve:

1

As the first factor is always positive, consider the sign of the 2nd factor.

2

3

The second factor is always positive and nonzero, therefor, only consider the sign of the 1st factor.

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