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Introduction

While we often represent the Earth as a flat circle on maps, it is actually a sphere—a perfectly round three-dimensional object. In geometry, when we divide a sphere exactly in half through its centre, we create a hemisphere.

Mastering the properties of a hemisphere is a core part of the GCSE Maths curriculum, specifically within the mensuration and 3D shapes topics. Understanding how to calculate its space (volume) and its exterior (surface area) is essential for solving real-world problems, from architectural domes to calculating the amount of paint needed for a bowl.

Theory: Volume and Surface Area

A hemisphere has two primary properties you need to calculate: Volume and Surface Area. Because a hemisphere is exactly half of a sphere, our formulas are derived directly from spherical geometry.

1. Volume of a Hemisphere

The volume represents the total 3D space occupied by the object. Since the volume of a full sphere is:

43πr3\dfrac{4}{3} \pi r^{3}

the volume of a hemisphere is simply half of that:

V=23πr3V = \dfrac{2}{3} \pi r^{3}
  • r is the radius (the distance from the centre to any point on the surface).
  • pi is approximately 3.142.

2. Surface Area of a Hemisphere

Calculating the surface area of a hemisphere is slightly more complex because it depends on whether the shape is hollow or solid.

  • Curved Surface Area (CSA): This is just the "skin" of the bowl and equals:

2πr22 \pi r^{2}
  • Total Surface Area (TSA): For a solid hemisphere, you must add the area of the flat circular base to the curved surface:
2πr2+πr2=3πr22 \pi r^{2} + \pi r^{2} = 3 \pi r^{2}
Illustration of a hemisphere with radius, center, base, height, TSA and CSA labelled.
Image Source: Gianpiero Placidi

Advanced Spherical Sections

Beyond the basic hemisphere, more complex parts of a sphere appear in higher-tier GCSE and A-Level content.

Spherical Cap and Segment

  • Spherical Cap: A portion of a sphere cut off by a single plane. Its area is calculated using the height (h) of the cap and the radius of the sphere (R):

Area=2πRhArea = 2 \pi R h

  • Spherical Segment: The region between two parallel planes cutting through a sphere. Its volume is given by:
Volume=16πh(3a2+3b2+h2)Volume = \dfrac{1}{6} \pi h (3a^{2} + 3b^{2} + h^{2})

  • where a and b are the radii of the two circular bases.

Spherical Wedge and Lune

When dealing with "slices" of a sphere, we often use radians for the central angle theta (θ) to simplify the calculations, as seen in professional geometric diagrams.

Spherical Lune: The 2D curved surface area of that specific wedge:

Area=2θr2Area = 2 \theta r^{2}

Spherical Wedge: A 3D "slice" of a sphere (like an orange segment) defined by a central angle theta in radians:

Volume=23θr3Volume = \dfrac{2}{3} \theta r^{3}

Illustration of spherical lune, wedge, cap and segment
Image Source: Gianpiero Placidi

Practice Questions and Solutions

1

A solid hemisphere has a radius of 6 cm. Calculate its total surface area in terms of π.

Solution

For a solid hemisphere, we use the Total Surface Area formula:

Substitute r = 6:



2

Calculate the volume of a hemisphere with a radius of 3 m. Use π = 3.142.

Solution

Use the volume formula:

Substitute r = 3:



3

A spherical lune has a central angle of π/4 radians and a radius of 4 cm. Find its area.

Solution

Use the lune area formula for radians:

Substitute the values:



4

A spherical wedge has a central angle of π/3 radians and a radius of 3 cm. Calculate its volume.

Solution

Use the wedge volume formula for radians:

Substitute the values:



5

Find the height of a spherical cap if its surface area is and the radius of the sphere is 5 cm.

Solution

Use the spherical cap area formula:

Substitute the known values:


Solve for h:


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Gianpiero Placidi

UK-based Chemistry graduate with a passion for education, providing clear explanations and thoughtful guidance to inspire student success.