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The equation of a circle is the locus of points on the plane that are equidistant from a fixed point called the center.   By squaring the equation, the following is obtained: If it is developed:  Another way to write the equation is obtained: The center is:  An equation of the type: can be a circle if:

1. The coefficients of x² and y² are 1 or if they both have the same coefficient that does not equal 1, all terms of the equation can be divided by the value of the coefficient.

2. There is no term in xy.

3. ### A Circle with the Origin as its Center

If the center of the circle coincides with the origin of the graph, the equation is reduced to: Determine the equation of the circle with its center at point (3, 4) and a radius of 2.   Given the equation of the circle x² + y² − 2x + 4y − 4 = 0, find the center and its radius.  Find the equation of the circle that passes through the points A = (2, 0), B = (2, 3), C = (1, 3).

Substituting x and y in the equation for the coordinates of the points, the following system is obtained:   Determine whether the equation 4x² + 4y² − 4x − 8y − 11 = 0 corresponds to a circle, and if so, calculate its center and specify the length of its radius.

## Example 1.

Since the coefficients of x² and y² are different from 1, divide by 4: ## Example 2.

There is no term in xy.

## Example 3. Since all three conditions are met, it is a circle.  Did you like the article?     (1 votes, average: 5.00 out of 5) Loading...

Emma

I am passionate about travelling and currently live and work in Paris. I like to spend my time reading, gardening, running, learning languages and exploring new places.

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