June 26, 2019

The volume of the solid revolution generated by rotating the curve f(x) around the x-axis and bounded by x = a and x = b, is given by:

1. Find the volume of a truncated cone that is generated by the rotation around the line y = 6 − x and bounded by the lines y = 0, x = 0, x = 4.

2. Calculate the volume generated by y = sin x when rotated about the x-axis.

3. Find the volume of the solid revolution generated by rotating the function f(x) = 1/2 + cos x (bounded by the x-axis and the lines x = 0 and x = π) around the x-axis.

4. Find the volume generated by the circle x² + y² − 4x = −3 rotating about the x-axis.

The center of the circumference is C(0, 1) and radius r = 1.

x-intercepts:

5. Calculate the volume generated by rotating around the x-axis, the site bounded by the graphs of y = 2x − x² and y = −x + 2.

The points of intersection between the parabola and the straight line:

The parabola is above the straight line in the interval of integration.

6. Calculate the volume generated by rotating the site bounded by the graphs of y = 6x − x² and y = x around the x-axis .

The points of intersection:

The parabola is above the straight line in the interval of integration.

7. Calculate the volume generated by a triangle of vertices A(3, 0), B(6, 3), C(8, 0) that rotates 360º around the x-axis.

The equation of the straight line that passes through AB:

The equation of the straight line that passes through BC:

8.Find the volume of the figure generated by rotating the ellipse around the x-axis.

As the ellipse is a symmetrical curve, the volume is 2 times the volume generated by the arc between x = 0 and x = a.

Nice!

Need a little bit more explanation!

1- There is a need to draw the graph to find which is upper function and which one is lower function.

2- There is a need to find points of intersection of the two curves…in case they are not given.