June 26, 2019

Chapters

- Exercise 1
- Exercise 2
- Exercise 3
- Exercise 4
- Exercise 5
- Exercise 6
- Exercise 7
- Exercise 8
- Exercise 9
- Exercise 10
- Exercise 11
- Exercise 12
- Solution of exercise 1
- Solution of exercise 2
- Solution of exercise 3
- Solution of exercise 4
- Solution of exercise 5
- Solution of exercise 6
- Solution of exercise 7
- Solution of exercise 8
- Solution of exercise 9
- Solution of exercise 10
- Solution of exercise 11
- Solution of exercise 12

Solve the following integrals:

## Exercise 1

## Exercise 2

## Exercise 3

## Exercise 4

## Exercise 5

## Exercise 6

## Exercise 7

## Exercise 8

## Exercise 9

## Exercise 10

## Exercise 11

## Exercise 12

## Solution of exercise 1

## Solution of exercise 2

## Solution of exercise 3

## Solution of exercise 4

## Solution of exercise 5

Equal the coefficients of the two members.

The first integral is of logarithmic type and the second has to be broken in two.

Multiply by 2 in the second integral.

The 2 in the numerator of the second integral transforms into 1 + 1.

Decompose the second integral into two others.

Solve the first two integrals.

Transform the denominator of a squared binomial.

Multiply the numerator and denominator by 4/3, to obtain one in the denominator.

Under the squared binomial, multiply by the square root of 4/3.

## Solution of exercise 6

Add and subtract 3 in the numerator, decompose into two fractions and in the first one remove common factor 3.

Multiply and divide in the first fraction by 2.

Transform the denominator of a squared binomial.

Realize a change of variable.

## Solution of exercise 7

## Solution of exercise 8

## Solution of exercise 9

Make the second integral.

## Solution of exercise 10

## Solution of exercise 11

## Solution of exercise 12