June 26, 2019

Chapters

A paticular case of the the **intermediate value theorem** is the **Bolzano's theorem**:

**Suppose that f(x) is a continuous function on a closed interval [a, b] and takes the values of the opposite sign at the extremes, and there is at least one c
(a, b) such that f(c) = 0.**

The **Bolzano's theorem **does not indicate the value or values of * c*, it only confirms their existance.

## Example

Verify that the equation x³ + x − 1 = 0 has at least one real solution in the interval [0,1].

We consider the function f(x) = x³ + x − 1, which is continuous on [0,1] because it is polynomial. We study the sign in the extremes of the interval:

First, consider the function f(x) = x³ + x − 1, which is continuous in [0,1] because it is polynomial. Then, study the sign in the extremes of the interval:

f(0) = −1 < 0

f(1) = 1 > 0

As the signs are different, **Bolzano's theorem** can be applied which determines that there is a **c****
(0. 1)** such that **f(c) = 0**. This process demonstrates that there is a solution in this interval.

I got what i actually wanted thanks for the solutions.

Is 1/infinity= infinity??

1/infinity=0 because infinity=1/0

We get 1/infinity =1×0/1 =0

All are so good.

Everything is decorated.

After giving theorem,please give two or more example.

Thank you

In the limit 1/infinity is zero

You really helped me out with this, thank you

thanks for the information

Super