Triangles are the fundamental building blocks of geometry. From the rigid structures of bridges to the complex calculations in navigation and surveying, understanding how to calculate missing lengths and angles is essential.

In GCSE Maths, you will progress from basic properties to advanced trigonometry. This guide covers everything you need to know about right-angled and non-right-angled triangles, including the Sine Rule, Cosine Rule, and trigonometric area formulas.

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Theory: Right-Angled Triangles

Right-angled triangles contain one angle of 90 degrees. There are two primary tools used for these triangles: Pythagoras' Theorem and SOH CAH TOA.

Pythagoras' Theorem

Used to find a missing side length when the other two sides are known:

a2+b2=c2 a^{2} + b^{2} = c^{2}

Where c is the hypotenuse (the longest side opposite the right angle).

Diagram of right angles triangle with labelled sides
Image Source: Gianpiero Placidi

Trigonometry (SOH CAH TOA)

Used to find a missing side or angle using the relationship between sides and angles.

sin(θ)=OppositeHypotenuse\sin(\theta) = \dfrac{Opposite}{Hypotenuse}

cos(θ)=AdjacentHypotenuse\cos(\theta) = \dfrac{Adjacent}{Hypotenuse}

tan(θ)=OppositeAdjacent\tan(\theta) = \dfrac{Opposite}{Adjacent}
Diagram illustrating the rule of SOHCAHTOA
Image Source: Gianpiero Placidi

Theory: Area of a Triangle

Depending on the information provided, there are two ways to calculate the area of a triangle.

1. Basic Formula

Used when the base and vertical height are known:

Area=12×base×heightArea = \dfrac{1}{2} \times base \times height

2. Trigonometric Formula

Used for any triangle when you know two sides and the included angle (the angle between them):

Area=12absin(C)Area = \dfrac{1}{2} ab \sin(C)

Theory: Sine and Cosine Rules

For non-right-angled triangles, we label the vertices with capital letters (A, B, C) and the opposite sides with lowercase letters (a, b, c).

The Sine Rule

Use this when you have "matching pairs" (an angle and its opposite side):

asinA=bsinB=csinC\dfrac{a}{\sin A} = \dfrac{b}{\sin B} = \dfrac{c}{\sin C}

The Cosine Rule

Use this for more complex setups.

  • To find a side:
a2=b2+c22bccosAa^{2} = b^{2} + c^{2} - 2bc \cos A
  • To find an angle:
cosA=b2+c2a22bc \cos A = \dfrac{b^{2} + c^{2} - a^{2}}{2bc}
Illustration of sine and cosine rule for non-right angled triangles
Image Source: Gianpiero Placidi

When to Use Each Formula

ScenarioKnown InformationRule to Use
Right-angled triangleTwo sides knownPythagoras
Right-angled triangleOne side and one angle knownSOH CAH TOA
Any triangleTwo sides and included angleArea = 1/2 ab sin C
Any triangleA matching side/angle pairSine Rule
Any triangleThree sides known (SSS)Cosine Rule (Angle)
Any triangleTwo sides and included angle (SAS)Cosine Rule (Side)

Worked Examples

Example 1: Pythagoras' Theorem

Question: A right-angled triangle has sides of 5 cm and 12 cm. Find the hypotenuse. Solution:

  1. Identify sides: a = 5, b = 12.
  2. Apply formula:
c2=52+122c^{2} = 5^{2} + 12^{2}

c2=25+144=169c^{2} = 25 + 144 = 169

c=169=13 cmc = \sqrt{169} = 13 \text{ cm}

Example 2: The Sine Rule

Question: In triangle ABC, angle A = 40, angle B = 60, and side a = 10 cm. Find side b.

Apply Sine Rule:

bsin60=10sin40\dfrac{b}{\sin 60} = \dfrac{10}{\sin 40}

Rearrange:

b=10×sin60sin40b = \dfrac{10 \times \sin 60}{\sin 40}

b13.47 cmb \approx 13.47 \text{ cm}

Practice Questions and Solutions

1

Find the length of the hypotenuse in a right-angled triangle with shorter sides of 3 cm and 4 cm.

Solution

Identify the sides:

Apply Pythagoras:




2

Calculate the area of a triangle where side a = 8 cm, side b = 10 cm, and the included angle C = 30 degrees.

Solution

Use the trigonometric area formula:

Substitute the values:

Since sin(30) is 0.5:


3

In triangle ABC, a = 7 cm, b = 10 cm, and angle C = 60 degrees. Find the length of side c using the Cosine Rule.

Solution

Apply the Cosine Rule for a side:

Substitute the values:





4

Use SOH CAH TOA to find the angle theta in a right-angled triangle where the Opposite side is 5 cm and the Hypotenuse is 10 cm.

Solution

Identify the correct ratio (Sine):

Substitute the values:


Find the inverse sine:


5

In triangle ABC, side a = 12 cm, angle A = 50 degrees, and angle B = 35 degrees. Find side b using the Sine Rule.

Solution

Apply the Sine Rule:

Rearrange to solve for b:

Calculate the value:


Summarise with AI:

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Gianpiero Placidi

UK-based Chemistry graduate with a passion for education, providing clear explanations and thoughtful guidance to inspire student success.