The best Maths tutors available
Poonam
5
5 (74 reviews)
Poonam
£100
/h
Gift icon
1st lesson free!
Paolo
4.9
4.9 (83 reviews)
Paolo
£35
/h
Gift icon
1st lesson free!
Sehaj
4.9
4.9 (60 reviews)
Sehaj
£60
/h
Gift icon
1st lesson free!
Anthony
5
5 (86 reviews)
Anthony
£15
/h
Gift icon
1st lesson free!
Johann
5
5 (60 reviews)
Johann
£50
/h
Gift icon
1st lesson free!
Tomi
5
5 (40 reviews)
Tomi
£75
/h
Gift icon
1st lesson free!
Imad
5
5 (27 reviews)
Imad
£95
/h
Gift icon
1st lesson free!
Harjinder
4.9
4.9 (165 reviews)
Harjinder
£25
/h
Gift icon
1st lesson free!
Poonam
5
5 (74 reviews)
Poonam
£100
/h
Gift icon
1st lesson free!
Paolo
4.9
4.9 (83 reviews)
Paolo
£35
/h
Gift icon
1st lesson free!
Sehaj
4.9
4.9 (60 reviews)
Sehaj
£60
/h
Gift icon
1st lesson free!
Anthony
5
5 (86 reviews)
Anthony
£15
/h
Gift icon
1st lesson free!
Johann
5
5 (60 reviews)
Johann
£50
/h
Gift icon
1st lesson free!
Tomi
5
5 (40 reviews)
Tomi
£75
/h
Gift icon
1st lesson free!
Imad
5
5 (27 reviews)
Imad
£95
/h
Gift icon
1st lesson free!
Harjinder
4.9
4.9 (165 reviews)
Harjinder
£25
/h
Gift icon
1st lesson free!
Let's go

How to Find Maxima and Minima

To find the local maxima and minima of a function , follow these steps:

Step 1 — Find the first derivative.

Step 2 — Set and solve for . These are the stationary points (also called critical points).

Step 3 — Find the second derivative.

Step 4 — Classify each stationary point using the second derivative test:

  • If , the point is a local minimum.
  • If , the point is a local maximum.
  • If , the test is inconclusive — use the first derivative (sign change) test instead.

Step 5 — Find the y-coordinates by substituting each -value back into the original function .

Worked Problems and Solutions

1

Exercise 1:

Solution

Solution of Exercise 1

First derivative:

Set :

Second derivative:

Classify:

At : > 0, so this is a local minimum.

At : <0, so this is a local maximum.

Y-coordinates:

Conclusion: Local maximum at . Local minimum at .

2

Exercise 2:

Solution

Solution of Exercise 2

First derivative:

Set :

Second derivative:

Classify:

At : <0, so this is a local maximum.

At : > 0, so this is a local minimum.

Y-coordinates:

Conclusion: Local maximum at . Local minimum at .

3

Exercise 3:

Solution

Solution of Exercise 3

First derivative:

Set :

Second derivative:

Classify:

At : <0, so this is a local maximum.

At : > 0, so this is a local minimum.

At : > 0, so this is a local minimum.

Y-coordinates:

Conclusion: Local maximum at . Local minima at and .

4

Exercise 4:

Solution

Solution of Exercise 4

First derivative (using the quotient rule):

Set :

The denominator is always positive, so set the numerator equal to zero:

Classify using the first derivative sign test:

For : we have > 0 and <0. The derivative changes from positive to negative, so this is a local maximum.

For : we have <0 and [latex]f'(0)=1[/latex]> 0. The derivative changes from negative to positive, so this is a local minimum.

Y-coordinates:

Conclusion: Local maximum at . Local minimum at .

5

Exercise 5:

Solution

Solution of Exercise 5

First derivative:

Set :

Second derivative:

Classify:

At : <0, so this is a local maximum.

At : > 0, so this is a local minimum.

Y-coordinates:

Conclusion: Local maximum at . Local minimum at .

6

Exercise 6:

Solution

Solution of Exercise 6

First derivative (using the product rule):

Set :

Since > 0 for all , we need:

Second derivative:

Classify:

At : <0, so this is a local maximum.

Y-coordinate:

Conclusion: Local maximum at . There are no local minima.

7

Exercise 7:

Solution

Solution of Exercise 7

Note: The domain is > 0.

First derivative:

Set :

Second derivative:

Classify:

At : <0, so this is a local maximum.

Y-coordinate:

Conclusion: Local maximum at . There are no local minima on the domain > 0.

Summarise with AI:

Did you like this article? Rate it!

4.00 (7 rating(s))
Loading...
Emma

Emma

I am passionate about travelling and currently live and work in Paris. I like to spend my time reading, gardening, running, learning languages and exploring new places.