In mathematics, a sequence is an ordered list of numbers governed by a specific rule or mapping:

(un)=u1,u2,u3,…,un,…for n∈ℕ(u_n) = u_1, u_2, u_3, \dots, u_n, \dots \quad \text{for } n \in \mathbb{N}

A monotone sequence (or monotonic sequence) is a sequence whose terms move in a single, consistent direction—either entirely non-increasing or entirely non-decreasing—throughout its entire domain. In simple terms, a monotonic sequence never alternates, fluctuates, or reverses direction.

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Classifications of Monotonicity

Monotonicity is formally categorised based on whether consecutive terms can be equal or must strictly change in value.

Graphical illustration of monotonic sequences both increasing and decreasing strictly
Image Source: Gianpiero Placidi

A. Increasing Sequences

  • Strictly Increasing: Each term is strictly greater than the preceding term:

un+1>unfor all n≥1u_{n+1} > u_n \quad \text{for all } n \ge 1

Example:2,5,8,11,14,…2, 5, 8, 11, 14, \dots where un=3n−1u_n = 3n - 1

  • Weakly Increasing (Non-Decreasing): Each term is greater than or equal to the preceding term:

un+1≥unfor all n≥1u_{n+1} \ge u_n \quad \text{for all } n \ge 1

Example:1,1,2,2,3,3,4,…1, 1, 2, 2, 3, 3, 4, \dots

B. Decreasing Sequences

  • Strictly Decreasing: Each term is strictly less than the preceding term:

un+1<unfor all n≥1u_{n+1} < u_n \quad \text{for all } n \ge 1

Example:1,12,14,18,…1, \dfrac{1}{2}, \dfrac{1}{4}, \dfrac{1}{8}, \dots where un=(12)n−1u_n = \left(\dfrac{1}{2}\right)^{n-1}

  • Weakly Decreasing (Non-Increasing): Each term is less than or equal to the preceding term:

un+1≤unfor all n≥1u_{n+1} \le u_n \quad \text{for all } n \ge 1

Example:10,10,9,9,8,8,7,…10, 10, 9, 9, 8, 8, 7, \dots

The Constant Sequence Case:

A constant sequence such as c,c,c,c,…c, c, c, c, \dots satisfies both un+1≥unu_{n+1} \ge u_n and un+1≤unu_{n+1} \le u_n. Mathematically, it is both weakly increasing and weakly decreasing, and is therefore classified as monotonic.

C. Non-Monotonic Sequences

If a sequence changes direction, it is non-monotonic:

  • Alternating Sequences: The terms switch signs or fluctuate around a value, such as un=(−1)nu_n = (-1)^n, giving −1,1,−1,1,…-1, 1, -1, 1, \dots
  • Periodic Sequences: The terms repeat in a cycle of length kk, such that un+k=unu_{n+k} = u_n.

Algebraic Tests to Prove Monotonicity

In exam questions, simply listing the first few terms is not sufficient proof of monotonicity. You must prove the condition holds for all general terms n∈ℕn \in \mathbb{N} using one of three standard algebraic methods.

Method 1: The Difference Test

Subtract the n-th term from the (n+1)-th term and analyse the sign:

  • If un+1−un>0u_{n+1} - u_n > 0 for all n∈ℕn \in \mathbb{N}, the sequence is strictly increasing.
  • If un+1−un≥0u_{n+1} - u_n \ge 0 for all n∈ℕn \in \mathbb{N}, the sequence is weakly increasing.
  • If un+1−un<0u_{n+1} - u_n < 0 for all n∈ℕn \in \mathbb{N}, the sequence is strictly decreasing.
  • If un+1−un≤0u_{n+1} - u_n \le 0 for all n∈ℕn \in \mathbb{N}, the sequence is weakly decreasing.

Method 2: The Ratio Test

Applicable only when all terms are strictly positive (un>0u_n > 0 for all n):

  • If un+1un>1\dfrac{u_{n+1}}{u_n} > 1 for all n∈ℕn \in \mathbb{N}, the sequence is strictly increasing.
  • If un+1un<1\dfrac{u_{n+1}}{u_n} < 1 for all n∈ℕn \in \mathbb{N}, the sequence is strictly decreasing.
  • If un+1un=1\dfrac{u_{n+1}}{u_n} = 1 for all n∈ℕn \in \mathbb{N}, the sequence is constant.

Method 3: The Derivative Test

If the sequence can be defined by a continuous real function f(x) such that un=f(n)u_n = f(n) for x≥1x \ge 1:

  • Find the first derivative f′(x)=ddx[f(x)]f'(x) = \dfrac{d}{dx}[f(x)].
  • If f′(x)>0f'(x) > 0 for all x≥1x \ge 1, then f(x) is strictly increasing, which proves (un)(u_n) is strictly increasing.
  • If f′(x)<0f'(x) < 0 for all x≥1x \ge 1 then f(x) is strictly decreasing, which proves (un)(u_n) is strictly decreasing.

The Monotone Convergence Theorem:

  1. If a sequence is monotonically increasing and bounded above, it is guaranteed to converge to a finite limit L, where L≤ML \le M.
  2. If a sequence is monotonically decreasing and bounded below, it is guaranteed to converge to a finite limit L, where L≥mL \ge m.
  3. An unbounded increasing sequence diverges to +∞+\infty; an unbounded decreasing sequence diverges to −∞-\infty.

Monotonicity in Standard Sequences

Arithmetic Sequences

The difference between consecutive terms is constant:

un+1−un=du_{n+1} - u_n = d
  • If common difference d > 0: Strictly increasing (unbounded above, diverges to +∞+\infty).
  • If common difference d < 0: Strictly decreasing (unbounded below, diverges to −∞-\infty).
  • If common difference d = 0: Constant (converges to a).

Geometric Sequences

The behaviour depends on the common ratio r:

  • If r > 1 and a > 0: Strictly increasing (diverges to +∞+\infty).
  • If 0 < r < 1 and a > 0: Strictly decreasing (bounded below by 0, converges to 0).
  • If r = 1: Constant sequence (un=au_n = a).
  • If r < 0: Non-monotonic because consecutive terms alternate signs.

Practice Questions & Solutions

1

Determine whether each of the following sequences is strictly increasing, strictly decreasing, or non-monotonic for

(a)

(b)

(c)

Solution

(a)

:

Since -4 <0,

is less than 0 so the sequence is strictly decreasing.

(b)

:

Here,

v_1 is less than v_2, but v_2 is greater than v_3.

The sequence is non-monotonic (alternating).

(c)

:

Combine over a common denominator:

Subtract:

Since , the numerator and denominator are positive, so .

The sequence is strictly increasing.

2

A sequence is given by

for

.

(a) Compute the first four terms .

(b) Find an expression for .

(c) Determine the integer value such that the sequence is strictly increasing for all .

Solution

(a) Evaluate the first four terms:

(b) Compute :

(c) For the sequence to be strictly increasing:

Since must be an integer, .

For , .

Therefore, the sequence is strictly increasing for all (so ).

3

Given the sequence

for

(a) Simplify the expression for .

(b) Use the ratio test to prove that is strictly decreasing.

(c) State the limit of as .

Solution

(a) Simplify :

(b) Apply the ratio test:

Since and for all : implies

Therefore, is strictly decreasing.

(c) Since is a geometric sequence with common ratio :

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Gianpiero Placidi

UK-based Chemistry graduate with a passion for education, providing clear explanations and thoughtful guidance to inspire student success.